Question

Sobre Funções Trigonométricas Inversas:
1. Calcule o valor de
a) arccos (-1).
b) arccos (-1/2)
c) arcsen (1/2)
d) arctg (√3)​

Answer 1

Explicação passo-a-passo:

a)

$\sf arccos~(-1)=\pi~rad~(180^{\circ})$

b)

$\sf arccos~\Big(-\dfrac{1}{2}\Big)=\dfrac{2\pi}{3}~rad~(120^{\circ})~ou~\dfrac{4\pi}{3}~rad~(240^{\circ})$

c)

$\sf arcsen~\Big(\dfrac{1}{2}\Big)=\dfrac{\pi}{6}~rad~(30^{\circ})~ou~\dfrac{5\pi}{6}~rad~(150^{\circ})$

d)

$\sf arctg~(\sqrt{3})=\dfrac{\pi}{3}~rad~(60^{\circ})~ou~\dfrac{4\pi}{3}~rad~(240^{\circ})$