Sobre a função f(x)=x^2+e^x assinale a única alternativa correta:
a)f'(x)=2x+ex
b)f''(x)=x
c )limx→∞f(x)=0
d)limx→0f(x)=0
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Solução!
![f(x)= x^{2} +e^{x} \\\\\
\boxed{f'(x)=2x+e^{x}}\\\\\\\
Vamos~~testar~~uma~~segunda~~derivada!\\\\\\
f'(x)=2x+e^{x}\\\\\\\
f''(x)=2+e^{x}\\\\\\\
\boxed{Resposta:f'(x)=2x+e^{x}~~\boxed{Alternativa~~A}}](https://tex.z-dn.net/?f=f%28x%29%3D+x%5E%7B2%7D+%2Be%5E%7Bx%7D+%5C%5C%5C%5C%5C%0A%5Cboxed%7Bf%27%28x%29%3D2x%2Be%5E%7Bx%7D%7D%5C%5C%5C%5C%5C%5C%5C%0AVamos%7E%7Etestar%7E%7Euma%7E%7Esegunda%7E%7Ederivada%21%5C%5C%5C%5C%5C%5C%0Af%27%28x%29%3D2x%2Be%5E%7Bx%7D%5C%5C%5C%5C%5C%5C%5C%0Af%27%27%28x%29%3D2%2Be%5E%7Bx%7D%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BResposta%3Af%27%28x%29%3D2x%2Be%5E%7Bx%7D%7E%7E%5Cboxed%7BAlternativa%7E%7EA%7D%7D "f(x)= x^{2} +e^{x} \\\\\
\boxed{f'(x)=2x+e^{x}}\\\\\\\
Vamos~~testar~~uma~~segunda~~derivada!\\\\\\
f'(x)=2x+e^{x}\\\\\\\
f''(x)=2+e^{x}\\\\\\\
\boxed{Resposta:f'(x)=2x+e^{x}~~\boxed{Alternativa~~A}}")
Boa tarde!
Bons estudos!
Solução!
Boa tarde!
Bons estudos!
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