Question

Sivida 260 em partes inversamentes proporcionais a 3,4 e 2 representados poer x,y e z os numeros procurados

Preciso prá já!!!

Answer 1

$\frac{p}{3} +\frac{p}{4} +\frac{p}{2} =260\\\\MMC=12\\\\\frac{4p+3p+6p}{12}=260\\ \\4p+3p+6p = 260 * 12\\\\13p = 3120\\\\p = 3120/13\\\\p=240$

$x=\frac{p}{3}= \frac{240}{3}=80 \\\\y=\frac{p}{4}= \frac{240}{4}=60\\ \\z=\frac{p}{2}= \frac{240}{2}=120$