Question

sistema linear 8x-12y=-64 20x+12y=8

Answer 1

$\left \{ {{8x-12y=-64} \atop {20x+12y=8}} \right.$

$(20x+12y)+(8x-12y)=8+(-64)$

$20x+12y+8x-12y=8-64$

$28x=-56$

$x=-\frac{56}{28}$

$x=-2$

$20x+12y=8$

$20.(-2)+12y=8$

$-40+12y=8$

$12y=8+40$

$12y=48$

$y=\frac{48}{12}$

$y=4$