Question

Simplifique: $\frac{x^2 - 10x + 21}{x^2 + x - 12}$

Answer 1

$\frac{x^2-10x+21}{x^2+x-12}=\\\\\\\frac{(x-3)(x-7)}{(x+4)(x-3)}=\\\\\\\boxed{\boxed{\frac{x-7}{x+4}}}$