Question

Simplifique sempre que possível:

Answer 1

Resposta:

$a)\\ \\ 3+(\frac{1}{2} )^{-2} =3+(\frac{1}{\frac{1}{2} }) ^{2} =3+(1.\frac{2}{1} )^{2} = 3+2^{2} =3+4=7$

$b)\\ \\ (\frac{2}{1} )^{-1} -\frac{5}{12} =(\frac{1}{\frac{2}{1} } )^{1} -\frac{5}{12} =\frac{1}{2} -\frac{5}{12} \\ \\ mmc=12\\ \\ \frac{6-5}{12} =\frac{1}{12}$

$c)\\ \\ (\frac{1}{4} )^{-1} -2^{0} =(\frac{1}{\frac{1}{4} } )^{1} -1=4-1=3$

$d)\\ \\ 3^{-2}+ 2^{-1}+3^{-1} +2^{-2} =\\ \\ \frac{1}{3^{2} }+ \frac{1}{2^{1} }+ \frac{1}{3^{1} } +\frac{1}{2^{2} } =\\ \\ \frac{1}{9} +\frac{1}{2} +\frac{1}{3} +\frac{1}{4} =\\ \\ mmc=36\\ \\ \frac{4+18+12+9}{36} =\frac{43}{36}$