simplifique pfv : 1/2a-1/2c+2/3a+1/3c
Soluções para a tarefa
Respondido por
1
1/2a+2/3a-1/2c+1/3c =
mmc 2a,3a,2c,3c = 6ac
(6ac:2a.1)/(6ac) + (6ac:3a.2)/(6ac) - (6ac:2c.1)/(6ac) + (6ac:3c.1)/(6ac) =
(3c)/(6ac) + (4c)/(6ac) - (3a)/(6ac) + (2a)/(6ac) =
(3c+4c-3a+2a)/(6ac) = (7c-a)/(6ac)
mmc 2a,3a,2c,3c = 6ac
(6ac:2a.1)/(6ac) + (6ac:3a.2)/(6ac) - (6ac:2c.1)/(6ac) + (6ac:3c.1)/(6ac) =
(3c)/(6ac) + (4c)/(6ac) - (3a)/(6ac) + (2a)/(6ac) =
(3c+4c-3a+2a)/(6ac) = (7c-a)/(6ac)
Perguntas interessantes