Question

simplifique os radicais
$\sqrt[10]{3 {}^{4} }$
$\sqrt[6]{5 {}^{12} }$
$\sqrt[3]{125} xb {}^{5}$
$\sqrt[4]{16} xa {}^{8}$

​

Answer 1

Resposta:

$\sqrt[10]{ {3}^{4} } = \sqrt[10 \div 2]{ {3}^{4 \div 2} } = \sqrt[5]{ {3}^{2} }$

$\sqrt[6]{ {5}^{12} } = \sqrt[6 \div 2]{ {5}^{12 \div2 } } = \sqrt[3]{ {5}^{6} } = {5}^{ \frac{6}{3} } = {5}^{2} = 25$

$\sqrt[3]{125} x {b}^{5} = \sqrt[3]{ {5}^{3} } x {b}^{5} = 5x {b}^{5}$

$\sqrt[4]{16} x {a}^{8} = \sqrt[4]{ {2}^{4} } x {a}^{8} = 2x {a}^{8}$

Espero ter ajudado.

Bons estudos.