Question

Simplifique os radicais :
A)√12
B)⁴√32
C)³√216
D)√256

Answer 1

A)
$\sqrt{12} = \sqrt{ {2}^{2} \times 3 } = 2 \sqrt{3}$


B)

$\sqrt[4]{32} = \sqrt[4]{ {2}^{4} \times 2} = 2 \sqrt[4]{2}$

C)

$\sqrt[3]{216} = \sqrt[3]{ {2}^{3} \times {3}^{3} } = 2 \times 3 = 6$


D)


$\sqrt{256} = \sqrt{ {2}^{8} } = {2}^{ \frac{8}{2} } = {2}^{4} = 16$