Question

simplifique os radicais: 10√1024
3√384
3√16
3√729

Answer 1

10√1024 = 10√2^10 = 10√2².2².2².2².2² = 10.2.2.2.2.2 = 320 (decompondo 1024 da 2^10)
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3√384
decompoe 384 = 
384/2
192/2
96/2
48/2
24/2
12/2
6/2
3/3
1

√384 = 3√2^7.3 = 3√2².2².2².2.3 = 3.2.2.2√2.3 = 24√6
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3√16
decompondo 16 
16/2
8/2
4/2
2/2
1

3√16 = 3√2^4 = 3√2².2² = 3.2.2 = 12
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3√729

decompondo 729
729/3
243/3
81/3
27/3
9/3
3/3
1

3√729 = 3√3^6 = 3√3².3².3² = 3.3.3.3 = 81