Question

simplifique (n-3)!/(n+1)!

Answer 1

(n-3)!/(n+1)!
(n-3)!/n.(n-1)(n-2)(n-3)!
1/n(n²-2n+2)

Answer 2

$\frac{(n - 3)!}{(n +1)!} = \frac{(n-3)!}{(n+1)n(n-1)(n-2)(n-3)!} = \frac{1}{(n^2-1)(n-2)n}$