Question

simplifique (n+2)!/(n+5)!

Answer 1

Explicação passo-a-passo:

${(n+2)!\over(n+5)!}=\\ \\ {(n+2)\over(n+2)(n+3)(n+4)(n+5)}=\\ \\ cancela~~(n+2)\\ \\ {1\over(n+3)(n+4)(n+5)$

ou assim

${(n+2)(n+3)(n+4)(n+5)\over(n+5)}=\\ \\ cancela~~(n+5)\\ \\ (n+2)(n+3)(n+4)$