Question

simplifique (n+2)!+(n+1)!/(n+3)!

Answer 1

Resposta:

[ (n+2)!+(n+1)!]/(n+3)!

[ (n+2)(n+1)!+(n+1)!]/[(n+3)(n+2)(n+1)!]

[ (n+2)+1]/[(n+3)(n+2)]

(n+3)/[(n+3)(n+2)]

=1/(n+2)