simplifique f(x)-f(p)/x-p sendo f(x)= 1/x e p=1
a Resposta é -1/x, mas eu queria entender como faz a resolução, Obrigado!
Soluções para a tarefa
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Olá!
![\displaystyle \mathsf{ f(x) = \frac{1}{x} } \\ \\ \\ \mathsf{ f(p) = \frac{1}{p} } \\ \\ \\ \mathsf{se \, \, \, p =1 \, \, \, temos:} \\ \\ \\ \mathsf{f(p)=1} \displaystyle \mathsf{ f(x) = \frac{1}{x} } \\ \\ \\ \mathsf{ f(p) = \frac{1}{p} } \\ \\ \\ \mathsf{se \, \, \, p =1 \, \, \, temos:} \\ \\ \\ \mathsf{f(p)=1}](https://tex.z-dn.net/?f=%5Cdisplaystyle+%5Cmathsf%7B+f%28x%29+%3D+%5Cfrac%7B1%7D%7Bx%7D+%7D+%5C%5C+%5C%5C+%5C%5C+%5Cmathsf%7B+f%28p%29+%3D+%5Cfrac%7B1%7D%7Bp%7D+%7D+%5C%5C+%5C%5C+%5C%5C+%5Cmathsf%7Bse+%5C%2C+%5C%2C+%5C%2C+p+%3D1+%5C%2C+%5C%2C+%5C%2C+temos%3A%7D+%5C%5C+%5C%5C+%5C%5C+%5Cmathsf%7Bf%28p%29%3D1%7D)
Portanto:
![\displaystyle \mathsf{ \frac{f(x)-f(p)}{x-p} } \\ \\ \\ \mathsf{ \frac{\displaystyle \frac{1}{x} - 1}{x-1} } \\ \\ \\ \mathsf{\frac{\displaystyle \frac{1-x}{x}}{x-1}} \\ \\ \\ \mathsf{ \frac{1-x}{x} \cdot \frac{1}{x-1} } \\ \\ \\ \mathsf{ \frac{-(x-1)}{x} \cdot \frac{1}{x-1} } \\ \\ \\ \mathsf{ -\frac{1}{x} } \displaystyle \mathsf{ \frac{f(x)-f(p)}{x-p} } \\ \\ \\ \mathsf{ \frac{\displaystyle \frac{1}{x} - 1}{x-1} } \\ \\ \\ \mathsf{\frac{\displaystyle \frac{1-x}{x}}{x-1}} \\ \\ \\ \mathsf{ \frac{1-x}{x} \cdot \frac{1}{x-1} } \\ \\ \\ \mathsf{ \frac{-(x-1)}{x} \cdot \frac{1}{x-1} } \\ \\ \\ \mathsf{ -\frac{1}{x} }](https://tex.z-dn.net/?f=%5Cdisplaystyle+%5Cmathsf%7B+%5Cfrac%7Bf%28x%29-f%28p%29%7D%7Bx-p%7D+%7D+%5C%5C+%5C%5C+%5C%5C+%5Cmathsf%7B+%5Cfrac%7B%5Cdisplaystyle+%5Cfrac%7B1%7D%7Bx%7D+-+1%7D%7Bx-1%7D+%7D+%5C%5C+%5C%5C+%5C%5C+%5Cmathsf%7B%5Cfrac%7B%5Cdisplaystyle+%5Cfrac%7B1-x%7D%7Bx%7D%7D%7Bx-1%7D%7D+%5C%5C+%5C%5C+%5C%5C+%5Cmathsf%7B+%5Cfrac%7B1-x%7D%7Bx%7D+%5Ccdot+%5Cfrac%7B1%7D%7Bx-1%7D+%7D+%5C%5C+%5C%5C+%5C%5C+%5Cmathsf%7B+%5Cfrac%7B-%28x-1%29%7D%7Bx%7D+%5Ccdot+%5Cfrac%7B1%7D%7Bx-1%7D+%7D+%5C%5C+%5C%5C+%5C%5C+%5Cmathsf%7B+-%5Cfrac%7B1%7D%7Bx%7D+%7D)
Portanto:
ricardosantos1oywiao:
como que chega em 1-x/x/x-1 ?
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