simplifique as radiações efetue as equações
a) √ 2+√32
b)√27+√ 3= c) 3√5+√ 20=
d) 2√2 + √8=
urgenteeee nao sei simplificar alguem pode ne explicar pfvr
Soluções para a tarefa
Resposta:
k) \sqrt{98}+5\sqrt{18}=\sqrt{98}+5\sqrt{18}=7\sqrt{2}+5(3\sqrt{2})=7\sqrt{2}+15\sqrt{2}=22\sqrt{2}
98
+5
18
=
98
+5
18
=7
2
+5(3
2
)=7
2
+15
2
=22
2
l) 3\sqrt{98}-2\sqrt{50}=3(7\sqrt{2})-2(5\sqrt{2})=21\sqrt{2}-10\sqrt{2}=11\sqrt{2}3
98
−2
50
=3(7
2
)−2(5
2
)=21
2
−10
2
=11
2
m) 3\sqrt{8}-7\sqrt{50}=3(2\sqrt{2})-7(5\sqrt{2})=6\sqrt{8}-35\sqrt{2}=-29\sqrt{2}3
8
−7
50
=3(2
2
)−7(5
2
)=6
8
−35
2
=−29
2
n) 2\sqrt{32}-5\sqrt{18}=2(4\sqrt{2})-5(3\sqrt{2})=8\sqrt{2}-15\sqrt{2}=-7\sqrt{2}2
32
−5
18
=2(4
2
)−5(3
2
)=8
2
−15
2
=−7
2
o) \sqrt{75}-2\sqrt{12}+\sqrt{27}=5\sqrt{3}-2(2\sqrt{3})+3\sqrt{3}=5\sqrt{3}-4\sqrt{3}+3\sqrt{3}=4\sqrt{3}
75
−2
12
+
27
=5
3
−2(2
3
)+3
3
=5
3
−4
3
+3
3
=4
3
p) \sqrt{12}-9\sqrt{3}+\sqrt{75}=2\sqrt{3}-9\sqrt{3}+5\sqrt{3}=-2\sqrt{3}
12
−9
3
+
75
=2
3
−9
3
+5
3
=−2
3
q) \sqrt{98}-\sqrt{18}-5\sqrt{32}=7\sqrt{2}-3\sqrt{2}+5(4\sqrt{2})=7\sqrt{2}-3\sqrt{2}+20\sqrt{2}=24\sqrt{2}
98
−
18
−5
32
=7
2
−3
2
+5(4
2
)=7
2
−3
2
+20
2
=24
2
r) 5\sqrt{180}+\sqrt{245}-17\sqrt{5}=6\sqrt{5}+7\sqrt{5}-17\sqrt{5}=-4\sqrt{5}5
180
+
245
−17
5
=6
5
+7
5
−17
5
=−4
5