Simplifique as fracoes algébicas
a) 5m-10\m²-m+4
b) 3+x\x²-9
c)4x²-4x+1\4x²-1
d) 2x-6\x²-6x+9
e) a²-8a+16\a²-16
efetue as operaçoes e simplifique,se possivel o resultado
a)7\2x -4\3x²
b)4\x-5\x-2
c) 7x_1\x²-4-4\x+2
d) 1\x-3-6\x²-9
Soluções para a tarefa
Respondido por
3
7/2x - 4/3x²
mmc = 6x² )
( 21x- 8)/6x²
b
4/x - 5/( x-2) =
mmc = x ( x - 2)
( 4(x - 2) - (5x) / x( x - 2) = ( 4x - 8 - 5x )/ x ( x - 2) = ( - x - 8)/ x ( x -2)
c
( 7x - 1)/( x²-4) - 4/( x + 2) =
mmc = x² - 4 ou ( x + 2)(x - 2)
[1( 7x - 1) - 4 ( x - 2)] / ( x - 2) ( x + 2) = ( 7x - 1 - 4x + 8)/ ( x - 2)(x + 2) =
( 3x + 7)/ ( x -2)( x + 2) = ( 3x + 7)/(x²-4)
d
1/( x - 3) - 6 / ( x²-9)
mmc = x² - 9 ou ( x + 3)(x -3) =
[ 1( x + 3) - 6 ]/ [( x + 3)(x -3) ] = ( x - 3) / [ ( x + 3) ( x - 3)]
corta x - 3 fica ( 1 ) / ( x + 3 )
==============================================================
a)
(5m-10)/ ( m² - m + 4) = 5 ( m - 2) / ( m - 2) ( m - 2) = 5/(m-2)>>>>> ( cortei m-2)
b
( 3 + x) / ( x² - 9) ou ( x + 3) / ( x² - 9) = ( x + 3) / [ (x + 3) ( x - 3) = 1/( x - 3)
c
(4x² - 4x +1 )/ ( 4x² - 1) =[( 2x - 1) ( 2x - 1)]/ [ ( 2x + 1)(2x-1) = ( 2x - 1)/ ( 2x + 1)
d
( 2x - 6) / ( x² - 6x + 9 ) = [2 ( x - 3) ]/[ ( x - 3) ( x - 3)] = 2/ ( x - 3)
e
( a² - 8a + 16 ) / ( a² - 16) = [ ( a - 4) ( a -4)] / [ ( a + 4) ( a - 4)] = ( a - 4)/( a + 4)
mmc = 6x² )
( 21x- 8)/6x²
b
4/x - 5/( x-2) =
mmc = x ( x - 2)
( 4(x - 2) - (5x) / x( x - 2) = ( 4x - 8 - 5x )/ x ( x - 2) = ( - x - 8)/ x ( x -2)
c
( 7x - 1)/( x²-4) - 4/( x + 2) =
mmc = x² - 4 ou ( x + 2)(x - 2)
[1( 7x - 1) - 4 ( x - 2)] / ( x - 2) ( x + 2) = ( 7x - 1 - 4x + 8)/ ( x - 2)(x + 2) =
( 3x + 7)/ ( x -2)( x + 2) = ( 3x + 7)/(x²-4)
d
1/( x - 3) - 6 / ( x²-9)
mmc = x² - 9 ou ( x + 3)(x -3) =
[ 1( x + 3) - 6 ]/ [( x + 3)(x -3) ] = ( x - 3) / [ ( x + 3) ( x - 3)]
corta x - 3 fica ( 1 ) / ( x + 3 )
==============================================================
a)
(5m-10)/ ( m² - m + 4) = 5 ( m - 2) / ( m - 2) ( m - 2) = 5/(m-2)>>>>> ( cortei m-2)
b
( 3 + x) / ( x² - 9) ou ( x + 3) / ( x² - 9) = ( x + 3) / [ (x + 3) ( x - 3) = 1/( x - 3)
c
(4x² - 4x +1 )/ ( 4x² - 1) =[( 2x - 1) ( 2x - 1)]/ [ ( 2x + 1)(2x-1) = ( 2x - 1)/ ( 2x + 1)
d
( 2x - 6) / ( x² - 6x + 9 ) = [2 ( x - 3) ]/[ ( x - 3) ( x - 3)] = 2/ ( x - 3)
e
( a² - 8a + 16 ) / ( a² - 16) = [ ( a - 4) ( a -4)] / [ ( a + 4) ( a - 4)] = ( a - 4)/( a + 4)
narleidepilar1:
obrigada,o outro é do mesmo jeito
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