Question

simplifique as frações

(a)90/48

(b)408/60

(c)56/28

(d)77/99​

Answer 1

$a) \: \frac{90}{48}^{ \div 2} = \frac{45}{24}^{ \div 3} = \frac{15}{8}$

$b) \: \frac{408}{60}^{ \div 4} = \frac{102}{15}^{ \div 3} = \frac{34}{3}$

$c) \: \frac{56}{28}^{ \div 4} = \frac{14}{7}^{ \div 7} = \frac{2}{1}$

$d) \: \frac{77}{99}^{ \div 11} = \frac{7}{9}$