Question

simplifique as frações:
a) 6!×8!/9!×3!

Answer 1

$\dfrac{6!*8!}{9!*3!}= \dfrac{6!*8!}{9*8!*3!}= \dfrac{6!}{9*3!}= \dfrac{6*5*4*3!}{9*3!}= \dfrac{6*5*4}{9}= \dfrac{120}{9}= \boxed{\dfrac{40}{3}}$