Question

Simplifique as expressoes , se poder deixar o calculo agradeco

Answer 1

Resposta:

a)

$\frac{n!}{(n-1)!}=\frac{n.(n-1)!}{(n-1)!}=n$

b)

$\frac{(n+4)!}{(n+2)!(n+3)!} =\frac{(n+4)(n+3)(n+2)!}{(n+2)!(n+3)!}=\frac{(n+4)(n+3)}{(n+3)!}=\frac{(n+4)(n+3)}{(n+3)(n+2)!}=\frac{n+4}{(n+2)!}$

c)

$\frac{(n-1)!+n!}{(n+1)!} =\frac{(n-1)1+n(n-1)!}{(n+1)n(n-1)!} =\frac{1+n}{(n+1)n} =\frac{1}{n}$