Question

simplifique as expressões e calcule as somas algébricas a seguir:
me ajudem,pleasee ❤️

Answer 1

A)

${5}^{3} \sqrt{3} + {2}^{3} \sqrt{3} - {2}^{3} \sqrt{3} + \sqrt{3} = \\ {5}^{3} \sqrt{3} + \sqrt{3} = \\ 125 \sqrt{3} + \sqrt{3} = \\ 126 \sqrt{3}$

B)

$\frac{3}{2} \sqrt{90} - \frac{1}{4} \sqrt{250} - \frac{1}{4} \sqrt{10} = \\ \frac{3}{2} \sqrt{9 \times 10} - \frac{1}{4} \sqrt{25 \times 10} - \frac{1}{4} \sqrt{10} \\ \frac{3}{2} \times 3 \sqrt{10} - \frac{1}{4} \times 5 \sqrt{10} - \frac{1}{4} \sqrt{10} = \\ \frac{9}{2} \sqrt{10} - \frac{5}{4} \sqrt{10} - \frac{1}{4 \ } \sqrt{10} = \\ \frac{18 \sqrt{10} - 5 \sqrt{10} - 1 \sqrt{10} }{4} = \\ \frac{12 \sqrt{10} }{4} = \\ 3 \sqrt{10}$

C)

$\sqrt{12} + \sqrt{75} + \sqrt{108} = \\ \sqrt{4 \times 3} + \sqrt{25 \times 3} + \sqrt{36 \times 3} = \\ 2 \sqrt{3} + 5 \sqrt{3} + 6 \sqrt{3} = \\ 13 \sqrt{3}$