Question

simplifique as expressões a seguir​

Answer 1

1

$\frac{x^{3}.y^{2}y^{5}x.x^{4}}{y^{7}}=\frac{x^{8}y^{7}}{y^{7}}=x^{8}$

2

$\frac{3.(\frac{-1}{2})^{2}+\frac{1}{4}}{3.(\frac{-1}{3})^{2} -\frac{3}{2} } = \frac{3.\frac{1}{4}+\frac{1}{4} }{3.\frac{1}{9}-\frac{3}{2} } = \frac{\frac{3}{4} +\frac{1}{4} }{\frac{1}{3}-\frac{3}{2} } = \frac{1}{\frac{1}{3}-\frac{3}{2} } = \frac{1}{\frac{2}{6}-\frac{9}{6} }=\frac{1}{\frac{-7}{6} } =-\frac{6}{7}$

3

$(\frac{2ab^{2}}{c^{3}})^{2}.(\frac{a^{2}c}{b})^{3} = (\frac{4a^{2}b^{4}}{c^{6}}).(\frac{a^{6}.c^{3}}{b^{3}})=\frac{4a^{8}b}{c^{3}}$

4

$\frac{3^{n+2}.3^{n}}{3.3^{n+1}} =\frac{3^{n+2}.3^{n}}{3^{n+2}} =3^{n}$

5

$\sqrt[3]{\frac{x^{2}.y^{2}.y^{4}}{x^{-7}}} = \sqrt[3]{x^{9}.y^{6}}=x^{3} .y^{2}$

*É propriedade de potência e radiciação, apenas. Pode me perguntar se houver qualquer dúvida.