Question

Simplifique as expressões:

A) (n +p)! / (n + p -1)!

Cálculos ok ​

Answer 1

Olá Maria Eduarda!

Explicação:

□ Vamos Analisar sua pergunta!

• A) (n +p)! / (n + p -1)!

□ Vamos calcular !

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□ Usando N! = N × (N-1)! Desenvolva a expressão!

$\bf \: \frac{ \red{(n + p) \times (n + p - 1)}}{(n + p - 1)}$

□ Reduza a expressão ( N+p-1)

$\bf \: n + p$

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□ Calcule na matemática!

$\begin{gathered}\mathsf{\dfrac{A_{n,p}}{C_{n,p}}=\dfrac{n!}{(n-p)!}\div\dfrac{n!}{p!\cdot(n-p)!}}\\\\\\ \mathsf{\dfrac{A_{n,p}}{C_{n,p}}=\dfrac{n!}{(n-p)!}\cdot\dfrac{p!\cdot(n-p)!}{n!}}\\\\\\ \mathsf{\dfrac{A_{n,p}}{C_{n,p}}=p!\cdot\dfrac{(n-p)!\cdot n!}{(n-p)!\cdot n!}}\\\\\\ \mathsf{\dfrac{A_{n,p}}{C_{n,p}}=p!}\end{gathered}$

□ Resposta :

$\huge \boxed{ \boxed{ \sf{(n + p - 1}}}$

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• Assinado : AnnaBrainlyMath

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Answer 2

Olá

Explicação:

□ Calcule na matemática!

$\begin{gathered} \begin{gathered}\mathsf{\dfrac{A_{n,p}}{C_{n,p}}=\dfrac{n!}{(n-p)!}\div\dfrac{n!}{p!\cdot(n-p)!}}\\\\\\ \mathsf{\dfrac{A_{n,p}}{C_{n,p}}=\dfrac{n!}{(n-p)!}\cdot\dfrac{p!\cdot(n-p)!}{n!}}\\\\\\ \mathsf{\dfrac{A_{n,p}}{C_{n,p}}=p!\cdot\dfrac{(n-p)!\cdot n!}{(n-p)!\cdot n!}}\\\\\\ \mathsf{\dfrac{A_{n,p}}{C_{n,p}}=p!}\end{gathered} \end{gathered}$

Resposta

$\huge \boxed{ \boxed{ \sf{(n + p - 1}}}$

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