Matemática, perguntado por Rosanariaab, 1 ano atrás

simplifique as equações , iliminando os denominadores

Anexos:

Soluções para a tarefa

Respondido por avengercrawl
1
Olá



A)

\displaystyle \mathsf{ \frac{5x}{6} = -\frac{13}{6} }\\\\\\\mathsf{ 5x = -\frac{13}{\diagup\!\!\!\!6}\cdot \diagup\!\!\!\!6 }\\\\\\\mathsf{5x=-13}\\\\\\\boxed{\mathsf{x= -\frac{13}{5} }}



B)

\displaystyle \mathsf{ \frac{-3x}{4} = \frac{2}{5} }\\\\\\\mathsf{ -3x = \frac{2}{5}\cdot 4 }\\\\\\\mathsf{-3x= \frac{8}{5} }\\\\\\\mathsf{3x= -\frac{8}{5} }\\\\\\\mathsf{x= -\frac{8}{5} \cdot  \frac{1}{3} }\\\\\\\boxed{\mathsf{x=- \frac{8}{15} }}




C)


\displaystyle\mathsf{ \frac{2x}{3} + \frac{1}{4} = \frac{3x-5}{2} }\\\\\\\mathsf{ \frac{8x+3}{12} = \frac{3x-5}{2} }\\\\\\\mathsf{8x+3= \frac{3x-5}{\diagup\!\!\!\!2}\cdot \diagup\!\!\!\!\!12}\\\\\\\mathsf{8x+3=(3x-5)\cdot 6}\\\\\\\mathsf{8x+3=18x-30}\\\\\\\mathsf{8x-18x=-30-3}\\\\\\\mathsf{-10x=-33}\\\\\\\mathsf{10x=33}\\\\\\\boxed{\mathsf{x= \frac{33}{10} }}

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