Question

simplifique a uma única potência
$( {2}^{3} \times {4}^{2} \times 16) {}^{ - 1} \times 32$
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Answer 1

Oi

Vamos reescrever todas em potência de base 2 e resolver ...

$(2^{3}.4^{2}.16)^{-1}.32\\\\\\(2^{3}.(2^{2})^{2}.2^{4})^{-1}.2^{5}\\\\\\(2^{3}.2^{4}.2^{4})^{-1}}.2^{5}\\\\\\(2^{3+4+4})^{-1}.2^{5}\\\\\\(2^{11})^{-1}.2^{5}\\\\\\2^{-11}.2^{5}\\\\\\2^{-11+5}=\boxed{2^{-6}}$

Bons estudos! :)