Question

Simplifique a potencia

Answer 1

Explicação passo-a-passo:

$\frac{8^{n+1}.4^{2n-3}}{16^3:(\frac{1}{4})^{3n-2}}$

$\frac{2^{3n+3}.4^{2n-3}}{16^3:(\frac{1}{4})^{3n-2}}$

$\frac{2^{3n+3}.2^{4n-6}}{16^3:(\frac{1}{4})^{3n-2}}$

$\frac{2^{3n+3}.2^{4n-6}}{2^{12}:(\frac{1}{4})^{3n-2}}$

$\frac{2^{3n+3}.2^{4n-6}}{2^{12}:2^{-6n+4}}$

$\frac{2^{7n-3}}{2^{6n+8}}$

$2^{n-11}$