Question

Simplifique a expressão literal: x2/2-{-3x2/4-[x2-×2/3-(5x2/2-2x2/3)]}





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Answer 1

    $\frac{x^2}{2}-[-\frac{3x^2}{4}-(x^2-\frac{x^2}{3}-(\frac{5x^2}{2}-\frac{2x^2}{3}))]=$

$=\frac{x^2}{2}-[-\frac{3x^2}{4}-(x^2-\frac{x^2}{3}-(\frac{3\times5x^2}{3\times2}-\frac{2\times2x^2}{2\times3}))]=$

$=\frac{x^2}{2}-[-\frac{3x^2}{4}-(x^2-\frac{x^2}{3}-(\frac{15x^2}{6}-\frac{4x^2}{6}))]=$

$=\frac{x^2}{2}-[-\frac{3x^2}{4}-(x^2-\frac{x^2}{3}-(\frac{15x^2-4x^2}{6}))]=$

$=\frac{x^2}{2}-[-\frac{3x^2}{4}-(x^2-\frac{x^2}{3}-\frac{11x^2}{6})]=$

$=\frac{x^2}{2}-[-\frac{3x^2}{4}-(\frac{6x^2}{6}-\frac{2x^2}{2\times3}-\frac{11x^2}{6})]=$

$=\frac{x^2}{2}-[-\frac{3x^2}{4}-(\frac{6x^2}{6}-\frac{2x^2}{6}-\frac{11x^2}{6})]=$

$=\frac{x^2}{2}-[-\frac{3x^2}{4}-(\frac{6x^2-2x^2-11x^2}{6})]=$

$=\frac{x^2}{2}-[-\frac{3x^2}{4}-(\frac{4x^2-11x^2}{6})]=$

$=\frac{x^2}{2}-[-\frac{3x^2}{4}-(\frac{-7x^2}{6})]=$

$=\frac{x^2}{2}-(-\frac{3x^2}{4}+\frac{7x^2}{6})=$

$=\frac{x^2}{2}-(-\frac{3\times3x^2}{3\times4}+\frac{2\times7x^2}{2\times6})=$

$=\frac{x^2}{2}-(-\frac{9x^2}{12}+\frac{14x^2}{12})=$

$=\frac{x^2}{2}-(\frac{-9x^2+14x^2}{12})=$

$=\frac{x^2}{2}-\frac{5x^2}{12}=$

$=\frac{6x^2}{6\times2}-\frac{5x^2}{12}=$

$=\frac{6x^2}{12}-\frac{5x^2}{12}=$

$=\frac{6x^2-5x^2}{12}=$

$=\frac{x^2}{12}$