Question

simplifique a expressao. acima :​

Answer 1

$\mathsf{\dfrac{2{a}^{2}x}{3}.{({a}^{2}.{x}^{2})}^{-\dfrac{2}{3}}}$

$\mathsf{\dfrac{2{a}^{2}x}{3}.\sqrt[3]{{({a}^{2}.{x}^{2})}^{-2}}}$

$\mathsf{\dfrac{2{a}^{2}x}{3}\sqrt[3]{{(a.x)}^{-3}.{(a.x)}^{-1}}}$

$\mathsf{\dfrac{2{a}^{2}x}{3}.{(a.x)}^{-1}.\sqrt[3]{\dfrac{1}{ax}}}$

$\dfrac{2\cancel{{a}^{2}}.\cancel{x}}{3}.\dfrac{1}{\cancel{a}\cancel{x}}.\dfrac{1}{\sqrt[3]{a.x}}$

$\mathsf{\dfrac{2a}{3}.\dfrac{1}{\sqrt[3]{ax}}}$

$\mathsf{\dfrac{2a}{3}.\dfrac{\sqrt[3]{{a}^{2}{x}^{2}}}{\sqrt[3]{{(a.x)}^{3}}}}$

$\mathsf{\dfrac{2\cancel{a}}{3}.\dfrac{\sqrt[3]{{(ax)}^{2}}}{\cancel{a}x}}$

$\mathsf{\dfrac{2\sqrt[3]{{a}^{2}.{x}^{2}}}{3x}}$

$\boxed{\boxed{\mathsf{\dfrac{2{a}^{2}x}{3}.{({a}^{2}.{x}^{2})}^{-\frac{2}{3}}=\dfrac{2\sqrt[3]{{a}^{2}.{x}^{2}}}{3x}}}}$

$\mathsf{\underline{Alternativa\:d}}$