Simplifique:
A) 3^√200:
B) 12^√81:
C) 6^√1000:
Me ajudem pfv
Soluções para a tarefa
Respondido por
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Olá.
![\mathsf{A)~\sqrt[3]{200}=}\\\\\mathsf{\sqrt[3]{2^3\cdot5^2}}\\\\\boxed{\mathsf{2\sqrt[3]{25}}}\\\\\\\mathsf{B)~\sqrt[12]{81}=}\\\\\mathsf{\sqrt[12]{3^4}=}\\\\\boxed{\mathsf{\sqrt[3]{3}}}
\\\\\\\mathsf{C)~\sqrt[6]{1000}=}\\\\\mathsf{\sqrt[6]{2^3\cdot3^3}=}\\\\\mathsf{\sqrt[2]{2\cdot3}=}\\\\\boxed{\mathsf{\sqrt[2]{6}}}](https://tex.z-dn.net/?f=%5Cmathsf%7BA%29%7E%5Csqrt%5B3%5D%7B200%7D%3D%7D%5C%5C%5C%5C%5Cmathsf%7B%5Csqrt%5B3%5D%7B2%5E3%5Ccdot5%5E2%7D%7D%5C%5C%5C%5C%5Cboxed%7B%5Cmathsf%7B2%5Csqrt%5B3%5D%7B25%7D%7D%7D%5C%5C%5C%5C%5C%5C%5Cmathsf%7BB%29%7E%5Csqrt%5B12%5D%7B81%7D%3D%7D%5C%5C%5C%5C%5Cmathsf%7B%5Csqrt%5B12%5D%7B3%5E4%7D%3D%7D%5C%5C%5C%5C%5Cboxed%7B%5Cmathsf%7B%5Csqrt%5B3%5D%7B3%7D%7D%7D%0A%5C%5C%5C%5C%5C%5C%5Cmathsf%7BC%29%7E%5Csqrt%5B6%5D%7B1000%7D%3D%7D%5C%5C%5C%5C%5Cmathsf%7B%5Csqrt%5B6%5D%7B2%5E3%5Ccdot3%5E3%7D%3D%7D%5C%5C%5C%5C%5Cmathsf%7B%5Csqrt%5B2%5D%7B2%5Ccdot3%7D%3D%7D%5C%5C%5C%5C%5Cboxed%7B%5Cmathsf%7B%5Csqrt%5B2%5D%7B6%7D%7D%7D "\mathsf{A)~\sqrt[3]{200}=}\\\\\mathsf{\sqrt[3]{2^3\cdot5^2}}\\\\\boxed{\mathsf{2\sqrt[3]{25}}}\\\\\\\mathsf{B)~\sqrt[12]{81}=}\\\\\mathsf{\sqrt[12]{3^4}=}\\\\\boxed{\mathsf{\sqrt[3]{3}}}
\\\\\\\mathsf{C)~\sqrt[6]{1000}=}\\\\\mathsf{\sqrt[6]{2^3\cdot3^3}=}\\\\\mathsf{\sqrt[2]{2\cdot3}=}\\\\\boxed{\mathsf{\sqrt[2]{6}}}")
Qualquer dúvida, deixe nos comentários.
Bons estudos.
Qualquer dúvida, deixe nos comentários.
Bons estudos.
kevinchevonica:
Obrigado
Nada não. ^^
Olá, desce encomodar, SI
SIMPLIFIQUE 20^√1024
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