Question

Simplifique √32X^4 y²/√4x y² para x > 0 e y > 0

Answer 1

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$\sqrt{32x^4y^2} \div \sqrt{4xy^2} = \\ \\ \sqrt{32\div4x^{4-1}y^{2-2}} = \\ \\ \sqrt{8x^3} = \sqrt{2^3x^3} = \sqrt{2^2.2.x^2.x} =2x \sqrt{2x}$