Question

simplifique: 2n! - (2n+ 1 )!/ 2n!

Answer 1

$\frac{2n!-(2n+1)!}{2n!}=\frac{2n!}{2n!}-\frac{(2n+1)!}{2n!}=1-\frac{(2n+1)2n!}{2n!}=1-(2n+1)=\\ \\ 1-2n-1=-2n$