Question

Simplificar

Vx . V32y^4.x

Com x e y reais positivos

Answer 1

$\sqrt{x} \cdot \sqrt{32y^4x} \\ =\sqrt{x\cdot32y^4x} \\ = \sqrt{32y^4x^2} \\ = \sqrt{2\cdot16y^4x^2} \\ = \sqrt{2}\cdot \sqrt{16y^4x^2} \\ = \sqrt{2}\cdot 4y^2x \\ = 4\sqrt{2}y^2x$