Question

Simplificar utilizando as propriedades da potenciação:(16a²b⁴/8ab^7)²

Answer 1

$( \frac{16a^{2}b^{4}}{8ab^{7}} )^{2}\\\\=(16:8a^{2-1}b^{4-7})^{2}\\\\=(2ab^{-3})^{2}\\\\=2^{2}a^{2}b^{-3.2}\\\\=\boxed{\boxed{4a^{2}b^{-6}}}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ok$

Answer 2

Resposta:

( \frac{16a^{2}b^{4}}{8ab^{7}} )^{2}\\\\=(16:8a^{2-1}b^{4-7})^{2}\\\\=(2ab^{-3})^{2}\\\\=2^{2}a^{2}b^{-3.2}\\\\=\boxed{\boxed{4a^{2}b^{-6}}}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ok

C

Explicação passo-a-passo: