Question

Simplificar: (n+4)! / (n+2)!

Answer 1

(n+4)!/(n+2)!= 
(n+4)(n+3)(n+2)!/(n+2)=
(n+4)(n+3)=
n(4+3)

Answer 2

$\frac{(n+4)!}{(n+2)!} = \frac{(n+4)(n+3)(n+2)!}{(n+2)!} = (n+4)(n+3) = \\ \\ n^{2}+3n+4n+12 = n^{2}+7n+12$

Espero ter ajudado.