Question

Simplificar as radicais.

Answer 1

a)

$\sqrt[8 \div 2]{ {3}^{6 \div 2}} = \sqrt[4]{ {3}^{3}} = \sqrt[4]{27}$

b)

$\sqrt[15 \div 5]{ {a}^{10 \div 5} } = \sqrt[3]{ {a}^{2} }$

c)

$\sqrt[4 \div 4]{ {b}^{8 \div 4} } = {b}^{2}$

d)

$\sqrt{16} = 4$

e)

$\sqrt[3]{64} = \sqrt[3 \div 3]{ {2}^{6 \div 3} } = {2}^{2} = 4$

f)

$\sqrt[3]{27} = \sqrt[3 \div 3]{ {3}^{3 \div 3} } = {3}^{1} = 3$

g)

$\sqrt{25 {x}^{2} } = 5x$

h)

$\sqrt[3]{8 {a}^{6} } = 2 {a}^{2}$

i)

$\sqrt{64 {x}^{4} {y}^{8}} = 8 {x}^{2} {y}^{4}$

j)

$\sqrt[4]{16 {x}^{8} } = 2 {x}^{2}$

k)

$\sqrt{25 {a}^{2} {b}^{4}} = 5a {b}^{2}$

l)

$\sqrt{12} = \sqrt{ {2}^{2}.3 } = 2 \sqrt{3}$

m)

$\sqrt{75} = \sqrt{3. {5}^{2} } = 5 \sqrt{3}$

n)

$\sqrt{18} = \sqrt{2. {3}^{2} } = 3 \sqrt{2}$

o)

$\sqrt{50} = \sqrt{2. {5}^{2} } = 5 \sqrt{2}$

p)

$\sqrt{12x} = \sqrt{ {2}^{2} .3.x} = 2 \sqrt{3x}$

q)

$\sqrt{48a} = \sqrt{ {2}^{4}.3.a} = 4 \sqrt{3a}$

r)

$\sqrt{ \frac{q}{ {x}^{2} } } = \frac{ \sqrt{q} }{x}$

s)

$\sqrt{ \frac{25 {a}^{6} }{ {x}^{10} } } = \frac{5 {a}^{3} }{ {x}^{5} }$

t)

$\sqrt{ \frac{49 {a}^{2} }{16} } = \frac{7a}{4}$