Question

simplificar a expressao (1+i elevado a 6)+3*(2-i elevado a 28)-4*(1-i elevado a 6)

Answer 1

Lembrando que em número complexos "i = √(-1)", temos que:

$(1 + i^6)+3*(2-i^{28})-4*(1-i^6)=\\\\=(1 + ( \sqrt{-1} )^6)+3*(2-( \sqrt{-1} )^{28})-4*(1-( \sqrt{-1} )^6)=\\\\=(1 + (-1)^3)+3*(2-(-1)^14)-4*(1-(-1)^3)=\\\\=(1 + (-1))+3*(2-(1))-4*(1-(-1))=\\\\=(1 -1)+3*(2-1)-4*(1+1))=\\\\=0+3*1-4*2=\\\\=0+3-8=\\\\=-5$