Question

simplificando o radical existente no numerador e colocando o fator comum em evidencia
A) 4+√32
______
8

Answer 1

Explicação passo-a-passo:

${4+\sqrt{32} \over8}=\\\\ {4+\sqrt{2^4.2} \over8}=\\\\\ \ {4+4\sqrt{2} \over8}=\\ \\ {\not4(1+\sqrt{2} )\over\not8_2}={1+\sqrt2\over2}$

Answer 2

$\sqrt{32}=\sqrt{{2}^{4}.2}=4\sqrt{2}$

$\mathsf{\dfrac{4+\sqrt{32}}{8}} \\\mathsf{\dfrac{4+4\sqrt{2}}{4.2}}\\\mathsf{\dfrac{\cancel4(1+\sqrt{2})}{\cancel4.2}}$

$\mathsf{\dfrac{4+\sqrt{32}}{8}=\dfrac{1+\sqrt{2}}{2}}$