Question

simplificando (m+3)!+(m+2)!/(m+3)!-(m+2)! obtemos.

Answer 1

$\dfrac{(m+3)!+(m+2)!}{(m+3)!-(m+2)!} =$

$\dfrac{(m+3).(m+2)!+(m+2)!}{(m+3).(m+2)!-(m+2)!} =$

$\dfrac{(m+2)!(m+3+1)}{(m+2)!(m+3-1)} =$

$\dfrac{m+4}{m+2}$