Question

Simplificando a expressão $\frac{2^{n+4}-2^{n+1} }{2^{n+4} }$ , obtemos:
a)$2^{n+1}$
b)7/8
c)-$2^{n+1}$
d)9/8

Answer 1

Explicação passo-a-passo:

$\sf E=\dfrac{2^{n+4}-2^{n+1}}{2^{n+4}}$

$\sf E=\dfrac{2^{n+1}\cdot(2^3-1)}{2^{n+1}\cdot2^3}$

$\sf E=\dfrac{2^3-1}{2^3}$

$\sf E=\dfrac{8-1}{8}$

$\sf \red{E=\dfrac{7}{8}}$

Letra B

Answer 2

Alternativa B ) 7/8

$\frac{ {2}^{n + 4} - 2 {}^{n + 1} }{ {2}^{n + 4} } = \frac{( {2}^{3} - 1) \times {2}^{n + 1} }{ {2}^{n + 4} } = \frac{8 - 1}{ {2}^{3} } = \frac{7}{8}$