simplificando a expressão [2^11/(2^5×2)³]^-2
Soluções para a tarefa
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Olá.
Usaremos as seguintes propriedades de potência:

![\mathsf{\left[\dfrac{2^{11}}{(2^5\cdot2)^3}\right]^{-2}=}\\\\\\
\mathsf{\left[\dfrac{2^{11}}{(2^6)^3}\right]^{-2}=}\\\\\\
\mathsf{\left[\dfrac{2^{11}}{2^{18}}\right]^{-2}=}\\\\\\
\mathsf{\left[\dfrac{2^{18}}{2^{11}}\right]^{2}=}\\\\\\
\mathsf{\dfrac{2^{36}}{2^{22}}=}\\\\
\mathsf{2^{36-22}=}\\\\
\mathsf{2^{14}=}\\\\\boxed{\mathsf{16.384}} \mathsf{\left[\dfrac{2^{11}}{(2^5\cdot2)^3}\right]^{-2}=}\\\\\\
\mathsf{\left[\dfrac{2^{11}}{(2^6)^3}\right]^{-2}=}\\\\\\
\mathsf{\left[\dfrac{2^{11}}{2^{18}}\right]^{-2}=}\\\\\\
\mathsf{\left[\dfrac{2^{18}}{2^{11}}\right]^{2}=}\\\\\\
\mathsf{\dfrac{2^{36}}{2^{22}}=}\\\\
\mathsf{2^{36-22}=}\\\\
\mathsf{2^{14}=}\\\\\boxed{\mathsf{16.384}}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cleft%5B%5Cdfrac%7B2%5E%7B11%7D%7D%7B%282%5E5%5Ccdot2%29%5E3%7D%5Cright%5D%5E%7B-2%7D%3D%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7B%5Cleft%5B%5Cdfrac%7B2%5E%7B11%7D%7D%7B%282%5E6%29%5E3%7D%5Cright%5D%5E%7B-2%7D%3D%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7B%5Cleft%5B%5Cdfrac%7B2%5E%7B11%7D%7D%7B2%5E%7B18%7D%7D%5Cright%5D%5E%7B-2%7D%3D%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7B%5Cleft%5B%5Cdfrac%7B2%5E%7B18%7D%7D%7B2%5E%7B11%7D%7D%5Cright%5D%5E%7B2%7D%3D%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7B%5Cdfrac%7B2%5E%7B36%7D%7D%7B2%5E%7B22%7D%7D%3D%7D%5C%5C%5C%5C%0A%5Cmathsf%7B2%5E%7B36-22%7D%3D%7D%5C%5C%5C%5C%0A%5Cmathsf%7B2%5E%7B14%7D%3D%7D%5C%5C%5C%5C%5Cboxed%7B%5Cmathsf%7B16.384%7D%7D)
Qualquer dúvida, deixe nos comentários.
Bons estudos.
Usaremos as seguintes propriedades de potência:
Qualquer dúvida, deixe nos comentários.
Bons estudos.
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= [2¹¹/(2⁵ · 2¹)³]⁻²
= [2¹¹/(2⁵⁺¹)³]⁻²
= [2¹¹/(2⁶)³]⁻²
= [2¹¹/(2⁶·³)]⁻²
= [2¹¹/2¹⁸]⁻²
= [2¹¹⁻¹⁸]⁻²
= [2⁻⁷]⁻²
= [2⁷]²
= 2⁷·²
= 2¹⁴
= 16384.