Question

simplificando a expressao 1-sen x. cos x. tg x obtemos?

Answer 1

$\boxed{1-sen x. cos x. tg x=1-senx.cos.\frac{senx}{cosx}=1-sen^2x=cos^2x}$

Answer 2

1-sen x. cos x. tg x = 1 - sen(x)*cos(x)*sen(x)/cos(x) = 1 - sen(x)*sen(x) = 1 - sen²(x) = cos²(x)