Question

simplificando √72 | 12 obstem se?

Answer 1

Vamos decompor 72 em números primos:

72 / 2
36 / 2
18 / 2
9 / 3
3 / 3
1             => 2².3².2

Agora resolvemos e simplificamos:

$\frac{\sqrt{72}}{12}= \frac{\sqrt{2^2\cdot3^2\cdot2}}{12}= \frac{2\cdot3\sqrt{2}}{12}=\\\\ \frac{(6\sqrt{2})^{\div6}}{12~{\div6}}=\ \textgreater \ \boxed{\boxed{\frac{\sqrt{2}}{2}}}$