Question

simplificando (2-²+4-³) : (4-² + 8-²) , obtém-se : ????

Answer 1

Boa noite Oseias!
Vamos começar a simplificar,

$\frac{(2^{-2}+ 4^{-3})}{ (4^{-2}+ 8^{-2})} = \frac{ ( \frac{1}{2})^{2}+(\frac{1}{4})^{3}}{ (\frac{1}{4})^{2} + (\frac{1}{8})^{2} } = \frac{\frac{1}{4}+ \frac{1}{64} }{ \frac{1}{16}+ \frac{1}{64} } = \frac{ \frac{17}{64}}{ \frac{5}{64} } = \frac{17}{64}. \frac{64}{5} = \frac{1088}{320} = 3,4$

Abraço!