Question

(Senx + tanx)(1-cosx)=

Answer 1

$( \sin(x) + \tan(x) )(1 - \cos(x) ) = \\ \sin( x ) - \sin(x) \cos(x) + \tan(x ) - \sin(x) = \\ \sin(x) ( \frac{1}{ \cos(x) } - \cos(x) ) = \\ \sin(x) ( \frac{1 - { \cos }^{2}(x) }{ \cos(x) }) = \\ \sin(x) \frac{ {\sin}^{2} (x) }{ \cos(x) } = \\ { \sin }^{2} (x) \tan(x)$