Question

sendox=(2^2)^3 , y=2^2^3 e z=2^3^2,o valor de xyz e?

Answer 1

Olá Jhonatan

x = (2^2)^3 = 4^3 = 64 

y = 2^2^3 = 2^8 = 256 

z = 2^3^2 = 2^9 = 512 

x*y*z = 64*256*512 = 8388608

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