Question

Sendof: R→IR uma função definida por f(x)=x^ 2 -3x-10. calcule:

a)f(-2)

b)f (-1)

c) f(0)

d) f(3)

e) f(5)

f)f(1/2 )=

Pfv me ajudem

Answer 1

f(x)= x² -3x -10

f(-2)= (-2)² -3.(-2) -10

f(-2)= 4 +6 -10

f(-2)= 10-10

f(-2)= 0

f(-1)= (-1)² -3.(-1) -10

f(-1)= 1 +3 -10

f(-1)= 4 - 10

f(-1)= - 6

f(0)= 0² - 3.0 -10

f(0)= 0 - 0 -10

f(0)= - 10

f(3)= 3² - 3.3 -10

f(3)= 9 - 9 -10

f(3)= -10

f(5)= 5² - 3.5 -10

f(5)= 25 - 15 -10

f(5)= 10 - 10

f(5)= 0

f(1/2)= (1/2)² - 3.1/2 - 10

f(1/2)= 1/4 - 3/2 -10

f(1/2) = 1 - 6 - 40

________

4

f(1/2)= -45/4