Question

sendo z1=3+2i e z2=4-5i o z1/z2 corresponde a) 2+23i/41+41. B) 2+23 C) 7+3i D) -3+22i

Answer 1

Z1/Z2= (3+2i)/(4-5i) = (3+2i )(4+5i)/(4-5i)(4-5i)  =
(12 +15i + 8i + 10i²)(16 - 25i²) = (12 + 23i -10) ( 16 + 25) = (2 + 23i) / 41=

2/41 + 23i/41