Question

sendo z1=2+ 3i e z2=5+8i calcule z1/z2

Answer 1

$\frac{Z1}{Z2} = \frac{2+3i}{5+8i} = \frac{(2+3i)(5-8i)}{(5+8i)(5-8i)} = \frac{10-16i+15i-24i^2}{25-64i^2} = \frac{34 - i}{25 + 64} = \frac{34}{89} - \frac{1}{89} i$