Question

sendo z=3-2i calcule:
a)Z²

Answer 1

$(3-2i)^{2} \\ (3-2i)(3-2i) \\ 9-6i-6i+4 i^{2} \\ 4 i^{2} -12i+9=0 \\ \\ \delta= b^{2} -4ac \\ \delta=(-12)^{2}-4.4.9 \\ \delta=0 \\ (VAZIO)$