Question

sendo z=(2-i)(3+i)-7,calcule z11

Answer 1

z=(2-i)(3+i)-7

z = 6 + 2i - 3i - i^2 - 7 ==> z =  6 + 2i - 3i - (-1) - 7

z = 6 + 2i - 3i + 1 - 7

z = - i