Question

Sendo y = (2³ . 2² . 2³)/ 2², a metade do valor de y vale:

Answer 1

Sabendo que:

$a^x+a^y=a^{x+y}$

$y=\frac{2^3*2^2*2^3}{2^2}=\frac{2^{3+2+3}}{2^2}=\frac{2^8}{2^2}=2^{8-2}=2^6$

$\frac{y}{2} =\frac{2^6}{2}=2^{6-1}=2^5$